How do you find the product $n^{8} \cdot n$ $n^8*n$ ?

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Answer 1 · 2017-02-13T21:38:01

$n^{8} \cdot n = n^{9}$ $n^8*n=n^9$

$n^{8} \cdot n$ $n^8*n$ means $n^{8} \cdot n^{1}$ $n^8*n^1$ .

Apply the product rule $a^{m} a^{n} = a^{m + n}$ $a^ma^n=a^(m+n)$ .

$n^{8} \cdot n = n^{8 + 1}$ $n^8*n=n^(8+1)$

$n^{8} \cdot n = n^{9}$ $n^8*n=n^9$

How do you find the product n^8*nn8⋅nn^8*n?