How do you find the range of $f (x) = [3 x - 4]$ $f(x)=[3x-4]$ if the domain is (0, 1, 2, 3)?

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Answer 1 · 2017-11-14T13:13:14

See a solution process below:

To find the range, substitute each value of the domain into the formula and calculate the result:

For x = 0

$f (0) = [(3 \times 0) - 4]$ $f(0) = [(3 xx 0) - 4]$

$f (0) = [0 - 4]$ $f(0) = [0 - 4]$

$f (0) = - 4$ $f(0) = -4$

For x = 1

$f (1) = [(3 \times 1) - 4]$ $f(1) = [(3 xx 1) - 4]$

$f (1) = [1 - 4]$ $f(1) = [1 - 4]$

$f (1) = - 3$ $f(1) = -3$

For x = 2

$f (2) = [(3 \times 2) - 4]$ $f(2) = [(3 xx 2) - 4]$

$f (2) = [6 - 4]$ $f(2) = [6 - 4]$

$f (2) = 2$ $f(2) = 2$

For x = 3

$f (3) = [(3 \times 3) - 4]$ $f(3) = [(3 xx 3) - 4]$

$f (3) = [9 - 4]$ $f(3) = [9 - 4]$

$f (3) = 5$ $f(3) = 5$

Therefore, the Range is: ${- 4, - 3, 2, 5}$ ${-4, -3, 2, 5}$

How do you find the range of f(x)=[3x−4]f(x)=[3x-4] if the domain is (0, 1, 2, 3)?