How do you find the range of x^3 - 5x3−5 given D = {0, 1, 2, 3, 4}?

1 Answer
Vinícius Ferraz
Jul 11, 2017

Im f = {f(0), f(1), f(2), f(3), f(4)}f={f(0),f(1),f(2),f(3),f(4)}

Explanation:

f(0) = 0^3 - 5 = -5f(0)=03−5=−5
f(1) = 1^3 - 5 = -4f(1)=13−5=−4
f(2) = 2^3 - 5 = 3f(2)=23−5=3
f(3) = 3^3 - 5 = 22f(3)=33−5=22
f(4) = 4^3 - 5 = 59f(4)=43−5=59

{-5,-4,3,22,59}{−5,−4,3,22,59}

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