How do you find the range of $y = z^2 - 3z$ ; given Domain = {-1, 0, 1, 2}?

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Answer 1 · 2016-09-08T14:04:15

$"The Range="{4,0,-2}$ .

$y=z^2-3z", and, let "D={-1,0,1,2}$ .

By, Range of the given function, we mean, the Set of all values of

$y$ , to be determined by using the values of $z$ choosing from the

given Domain Set, here, $D$ .

Thus, in Notation, the Range $={y=z^2-3z : z in D}$ .

Now, $z=-1 rArr y=z^2-3z=(-1)^2-3(-1)=1+3=4$

$z=0 rArr y=0$

$z=1 rArr y=-2$

$z=2 rArr y=-2$

Therefore, $"The Range="{4,0,-2}$ .

How do you find the range of y = z^2 - 3zy = z^2 - 3z; given Domain = {-1, 0, 1, 2}?