How do you find the rectangular coordinate of $(-4, pi/3)$ ?

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Answer 1 · 2015-11-11T13:07:11

$pi/3$ is in quadrant I. However, the negative value for the magnitude places the coordinate into quadrant III

$x = -4cos(pi/3)=-4(1/2)=-2$
$y=-4sin(pi/3)=-4(sqrt3/2)=-2sqrt3$

rectangular coordinate $=(-2,-2sqrt3)$

hope that helped

How do you find the rectangular coordinate of (-4, pi/3) (-4, pi/3)?