How do you find the remainder for $(x^3+10x^2-4)div(x+10)$ ?

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Answer 1 · 2016-11-26T09:44:09

The remainder is $=-4$

Let $f(x)=x^3+10x^2-4$

To find the remainder when $f(x)$ is divided by $(x-a)$

$f(x)=(x-a)*q(x)+r$

when $x=a$

$f(a)=(a-a)*q(a)+r$

$f(a)=0+r=r$

Here, $f(x)=x^3+10x^2-4$

and $a=-10$

So, $f(-10)=-1000+1000-4=-4$

How do you find the remainder for (x^3+10x^2-4)div(x+10)(x^3+10x^2-4)div(x+10)?