How do you find the remainder when $f(x)=5x^6-3x^3+8; x+1$ ?

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Answer 1 · 2016-05-07T15:59:01

The remainder theorem states that whenever polynomial function $f(x)$ is divided by $x - a$ the remainder is given by evaluating $f(a)$

$x + 1 = 0$
$x = -1$

You will evaluate $f(-1)$

$f(-1) = 5(-1)^6 - 3(-1)^3 + 8$

$f(-1) = 5(1) - 3(-1) + 8$

$f(-1) = 5 + 3 + 8$

$f(-1) = 16$

Hence, the remainder will be 16.

Hopefully this helps!

How do you find the remainder when f(x)=5x^6-3x^3+8; x+1f(x)=5x^6-3x^3+8; x+1?