How do you find the remainder when $x^{2} + 3 x + 4$ $x^2 + 3x + 4$ is divided by x – 5?

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Answer 1 · 2016-01-12T01:16:32

The Remainder Theorem tell us that when dividing by $x - 5$ $x-5$ , the remainder will equal $f (5)$ $f(5)$

Remainder $= f (5) = 5^{2} + 3 (5) + 4 = 44$ $= f(5)=5^2+3(5)+4=44$

hope that helps

How do you find the remainder when x2+3x+4x^2 + 3x + 4 is divided by x – 5?