Question

How do you find the second derivative of `f(t)=t^3-4t^2`?

Answer 1

`(d^2f)/dt^2 = 6t - 8`

Explanation:

The power rule states that `(x^n)' = nx^(n-1)`. We can use it to find the first derivative:

`(df)/(dt) = 3t^2 - 8t`

We can use the power rule again to find the second derivative.

`(d^2f)/(dt^2) = 6t - 8`.