How do you find the simplest radical form of 32?

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Answer 1 · 2017-04-07T13:46:45

$4sqrt2$

$color(blue)(sqrt32$

We need to get it into its simplest form. So, split it into prime factors

$rarrsqrt(2*2*2*2*2)$

$rarrsqrt(underbrace(2*2)*underbrace(2*2)*2)$

$rarr2*2sqrt2$

$color(green)(rArr4sqrt2$

Hope this helps!... :)