How do you find the six trigonometric functions of $(5pi)/3$ degrees?

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Answer 1 · 2015-05-14T02:18:05

Use the trig unit circle as proof.

$sin ((5pi)/3) = sin (-pi/3 + 2pi) = -sin (pi/3) = (-sqr3)/2$

$cos ((5pi)/3) = cos (-pi/3 + 2pi) = cos (pi/3) = 1/2$

$tan ((5pi)/3) = (-sqr3/2).(2/1) = -sqr3$

$cot ((5pi)/3) = (-sqr3)/3$

$sec ((5pi)/3) = 2$

$csc ((5pi)/3) = ((-2sqr3)/3)$

How do you find the six trigonometric functions of (5pi)/3(5pi)/3 degrees?