How do you find the slant asymptote of #{-9 x^3 - 9 x^2 + 28 x + 9 }/{3 x^2 + 6 x + 2}#?

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Answer 1 · 2016-07-29T17:31:52

#y = -3x+3#

We can long divide the coefficients like this:

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to find that:

#(-9x^3-9x^2+28x+9)/(3x^2+6x+2) = -3x+3+(16x+3)/(3x^2+6x+2)#

So the slant asymptote is:

#y = -3x+3#