How do you find the slope given $2 x - 3 y = 12$ $2x-3y=12$ ?

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Answer 1 · 2018-03-29T11:19:56

$\frac{2}{3}$ $2/3$

So you want to put the equation back into the linear equation $y = m x + c$ $y=mx+c$

As $m$ $m$ is the slope

Minus $2 x$ $2x$ from both sides
$- 3 y = 12 - 2 x$ $-3y=12-2x$

Divide by -3 on both sides

$y = \frac{12 - 2 x}{- 3}$ $y=(12-2x)/-3$

Break the Right hand side into two fractions

$y = \frac{12}{- 3} + \frac{- 2}{- 3} x$ $y=12/-3+(-2)/-3x$ or $y = \frac{- 2}{- 3} x + \frac{12}{- 3}$ $y=(-2)/-3x+12/-3$

Simplfy

$y = \frac{2}{3} x - 4$ $y=2/3x-4$

So the slope is $\frac{2}{3}$ $2/3$

How do you find the slope given 2x-3y=122x−3y=122x-3y=12?