How do you find the slope given $2 y = 8 x - 3$ $2y = 8x − 3$ ?

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Answer 1 · 2016-04-10T00:24:08

The gradient of the line is 4.

Consider the Gradient Form of a linear equation:

$y = m x + c$ $y=mx+c$
Where $m$ $m$ is the gradient of the slope.
and $c$ $c$ is the constant term (effectively the $y$ $y$ intercept)

**Let's now rearrange your equation into Gradient Form: **

$2 y = 8 x - 3$ $2y=8x-3$
$y = \frac{8 x - 3}{2}$ $y=(8x-3)/2$
$y = 4 x - \frac{3}{2}$ $y=4x-3/2$

Therefore, by inspecting the coefficient of $x$ $x$ (the $m$ $m$ term), we can see that the gradient of the line is 4.

How do you find the slope given 2y = 8x − 32y=8x−32y = 8x − 3?