How do you find the slope given #y=-12#?

1 Answer
Aug 8, 2015

The slope of #y = -12# is #0#

Explanation:

Since #y= -12# is a horizontal line, the value of #y# does not change regardless of how much #x# changes.

So the slope #=("change in " y)/("change in "x") = 0#

Alternately, you could re-write the given equation in slope-intercept form (that is #y = mx+b#)
to get
#color(white)("XXXX")##y = 0*x + (-12)#
to get a slope of #m=0#