How do you find the slope of a line passing through points (-6,3) and (-6,39)?

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How do you find the slope of a line passing through points (-6,3) and (-6,39)?

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Answer 1 · 2016-03-02T22:11:28

No Slope

Explanation:

The formula for the slope of a line based upon two coordinate points is

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2-y_1)/(x_2-x_1)$

For the coordinate points $(- 6, 3) and (- 6, 39)$ $(-6,3) and (-6,39)$
$x_{1} = - 6$ $x_1 = -6$
$x_{2} = - 6$ $x_2 = -6$
$y_{1} = 3$ $y_1 = 3$
$y_{2} = 39$ $y_2 = 39$

$m = \frac{39 - 3}{- 6 - (- 6)}$ $m = (39-3)/(-6-(-6))$
$m = \frac{36}{0}$ $m = 36/0$
Because the denominator of the slope is 0 this means there is no run and therefore no slope.

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How do you find the slope of a line passing through points (-6,3) and (-6,39)?

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