How do you find the solution set for 5x² - 30x = -25 ?

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Answer 1 · 2015-05-24T14:04:25

$5 x^{2} - 30 x + 25 = 0$ $5x^2-30x+25=0$

$5 (x^{2} - 6 x + 5) = 0$ $5(x^2-6x+5)=0$

$\Rightarrow x^{2} - 6 x + 5 = 0$ $=> x^2-6x+5=0$

$x^{2} - 5 x - x + 5 = 0$ $x^2-5x-x+5=0$

$x (x - 5) - 1 (x - 5) = 0$ $x(x-5)-1(x-5)=0$

$\Rightarrow (x - 5) (x - 1) = 0$ $=>(x-5)(x-1)=0$

$x = 5, 1$ $x=5,1$