How do you find the solution to the quadratic equation $2x^2-5=0$ ?

Question

3837 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-12T22:14:10

Starting with $2x^2 - 5 = 0$ , first add 5 to both sides to get:

$2x^2 = 5$

Divide both sides by 2 to get:

$x^2 = 5/2$

Take the square root of both sides (allowing both positive and negative roots) to get:

$x = +-sqrt(5/2) = +-sqrt(5)/sqrt(2)$

How do you find the solution to the quadratic equation 2x^2-5=02x^2-5=0?