How do you find the solution to the quadratic equation 2x^2 + 7 = 3x? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer sankarankalyanam Jun 18, 2018 color(maroon)(x_+ = (3 + i sqrt(47)) / 4, x_- = (3 - i sqrt(47))/4 Explanation: 2x^2 + 7 = 3x 2x^2 - 3x + 7 = 0 ![) a = 2, b = -3, c = 7 x = (-(-3) +- sqrt((-3)^2 - (4 * 2 * 7)))/(2 * 2) x = (3 +- sqrt(9 - 56) ) / 4 x = (3 +- sqrt(-47)) / 4 color(maroon)(x_+ = (3 + i sqrt(47)) / 4, x_- = (3 - i sqrt(47))/4 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 3289 views around the world You can reuse this answer Creative Commons License