Question

How do you find the solution to the quadratic equation `3x^2 + 24x - 9 = 0`?

Answer 1

`3x^2+24x-9 = 0`
is equivalent (after dividing both sides by 3) to
`x^2+8x-3 = 0`

Using the quadratic formula for roots
`x= (-b+-sqrt(b^2-4ac))/(2a)`

`x= (-6+-sqrt(64+12))/2`

`x=-3 +-sqrt(19)`