How do you find the solution to the quadratic equation $3x^2 + 24x - 9 = 0$ ?

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Answer 1 · 2015-05-05T21:48:18

$3x^2+24x-9 = 0$
is equivalent (after dividing both sides by 3) to
$x^2+8x-3 = 0$

Using the quadratic formula for roots
$x= (-b+-sqrt(b^2-4ac))/(2a)$

$x= (-6+-sqrt(64+12))/2$

$x=-3 +-sqrt(19)$

How do you find the solution to the quadratic equation 3x^2 + 24x - 9 = 03x^2 + 24x - 9 = 0?