How do you find the solution to the quadratic equation $3 x^{2} + 24 x - 9 = 0$ $3x^2 + 24x - 9 = 0$ ?

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Answer 1 · 2015-05-05T21:48:18

$3 x^{2} + 24 x - 9 = 0$ $3x^2+24x-9 = 0$
is equivalent (after dividing both sides by 3) to
$x^{2} + 8 x - 3 = 0$ $x^2+8x-3 = 0$

Using the quadratic formula for roots
$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x= (-b+-sqrt(b^2-4ac))/(2a)$

$x = \frac{- 6 \pm \sqrt{64 + 12}}{2}$ $x= (-6+-sqrt(64+12))/2$

$x = - 3 \pm \sqrt{19}$ $x=-3 +-sqrt(19)$

How do you find the solution to the quadratic equation 3x2+24x−9=03x^2 + 24x - 9 = 0?