How do you find the solution to the quadratic equation $x^{2} - 3 x = 10$ $x^2-3x=10$ ?

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How do you find the solution to the quadratic equation $x^{2} - 3 x = 10$ $x^2-3x=10$ ?

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Answer 1 · 2015-05-28T04:38:36

$y = x^{2} - 3 x - 10$ $y = x^2 - 3x - 10$ = (x - p)(x - q).
Find p and q knowing product (c = -10) and sum (-b = 3). Compose factor pairs of (-10)--> (-2, 5). This sum is 3 = -b. Then the 2 real roots are: -2 and 5.

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How do you find the solution to the quadratic equation $x^{2} - 3 x = 10$ $x^2-3x=10$ ?

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How do you find the solution to the quadratic equation $x^{2} - 3 x = 10$ $x^2-3x=10$ ?