How do you find the solution to the quadratic equation $x^2-4x-5=0$ ?

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Answer 1 · 2015-05-24T19:02:19

y = x^2 - 4x - 5 = 0.

Use the TIP 1 for shortcut.

Since a - b + c = 0, one real root is (-1) and the other is (-c/a = 5)

How do you find the solution to the quadratic equation x^2-4x-5=0x^2-4x-5=0?