How do you find the solution to the quadratic equation $x^{2} + x - 42 = 0$ $x^2+ x - 42 = 0$ ?

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Answer 1 · 2015-05-05T00:33:25

Factor the expression on the left side:
$x^{2} + x - 42 = 0$ $x^2+x-42 = 0$

$(x + 7) (x - 6) = 0$ $(x+7)(x-6) = 0$

So either $(x + 7) = 0$ $(x+7)=0$ or $(x - 6) = 0$ $(x-6)=0$

$x = - 7$ $x=-7$ or $x = + 6$ $x=+6$

How do you find the solution to the quadratic equation x2+x−42=0x^2+ x - 42 = 0?