How do you find the stationary points of the function $y=x^2+6x+1$ ?

Question

11104 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-10T12:03:02

$(-3,-8)$

The stationary points of a function are when $dy/dx=0$

$y=x^2+6x+1$

$dy/dx=2x+6$

$dy/dx=0=2x+6$

$x=-6/2=-3$

$(-3)^2+6(-3)+1=9-18+1=-8$

Stationary point occurs at $(-3,-8)$

How do you find the stationary points of the function y=x^2+6x+1y=x^2+6x+1?