How do you find the sum given $Sigma 1/j$ from j=3 to 5?

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Answer 1 · 2016-11-13T00:56:37

$sum_(j=3)^5 1/j = 47/30$

There are only a couple of terms, so let us just write out the sum in full as follows:

$sum_(j=3)^5 1/j = 1/3 + 1/4 + 1/5$
$:. sum_(j=3)^5 1/j = (20 + 15 + 12)/60$
$:. sum_(j=3)^5 1/j = 47/30$

How do you find the sum given Sigma 1/jSigma 1/j from j=3 to 5?