How do you find the sum or difference of $(2ab-3a+4b)+(5a+4ab)$ ?

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Answer 1 · 2017-07-03T15:17:40

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$2ab - 3a + 4b + 5a + 4ab$

Next, group like terms:

$-3a + 5a + 2ab + 4ab + 4b$

Now, combine like terms:

$(-3 + 5)a + (2 + 4)ab + 4b$

$2a + 6ab + 4b$

If necessary, you can factor a $2$ out of each term giving:

$(2 * a) + (2 * 3ab) + (2 * 2b)$

$2(a + 3ab + 2b)$

How do you find the sum or difference of (2ab-3a+4b)+(5a+4ab)(2ab-3a+4b)+(5a+4ab)?