How do you find the sum or difference of $(2c^2+6c+4)+(5c^2-7)$ ?

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Answer 1 · 2017-05-24T23:49:21

$7c^2+6c-7$

See the explanation for the process.

The parentheses are unnecessary because the two expressions are being added, so you are finding the sum of the terms.

$2c^2+6c+4+5c^2-7$

Group like terms.

$(2c^2+5c^2)+(6c)-(7)$

Combine like terms.

$7c^2+6c-7$

How do you find the sum or difference of (2c^2+6c+4)+(5c^2-7)(2c^2+6c+4)+(5c^2-7)?