How do you find the sum or difference of (2x+3x^2)-(7-8x^2)?
1 Answer
Jul 23, 2017
Explanation:
(2x+3x^2)+[-1\cdot(7-8x^2)]
(2x+3x^2)+[-1(7)+(-1)(-8x^2)] apply distributive property to second half
(2x+3x^2)+[-7+8x^2] simplify
2x+3x^2-7+8x^2 remove parentheses and change signs where needed
2x+11x^2-7 add like terms
11x^2+2x-7 reorder to quadratic format