How do you find the sum or difference of #(3z^2+2z-1)+(z^2-6)#?

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Answer 1 · 2017-05-08T13:42:43

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#3z^2 + 2z - 1 + z^2 - 6#

Next, group like terms:

#3z^2 + z^2 + 2z - 1 - 6#

Now, combine like terms:

#3z^2 + 1z^2 + 2z - 1 - 6#

#(3 + 1)z^2 + 2z + (-1 - 6)#

#4z^2 + 2z + (-7)#

#4z^2 + 2z - 7#