How do you find the sum or difference of $(3z^2+2z-1)+(z^2-6)$ ?

Question

1740 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-08T13:42:43

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$3z^2 + 2z - 1 + z^2 - 6$

Next, group like terms:

$3z^2 + z^2 + 2z - 1 - 6$

Now, combine like terms:

$3z^2 + 1z^2 + 2z - 1 - 6$

$(3 + 1)z^2 + 2z + (-1 - 6)$

$4z^2 + 2z + (-7)$

$4z^2 + 2z - 7$

How do you find the sum or difference of (3z^2+2z-1)+(z^2-6)(3z^2+2z-1)+(z^2-6)?