How do you find the sum or difference of $(4 + 2 a^{2} - 2 a) - (3 a^{2} - 8 a + 7)$ $(4+2a^2-2a)-(3a^2-8a+7)$ ?

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Answer 1 · 2017-01-25T12:19:10

$- a^{2} + 6 a - 3$ $-a^2+6a-3$

$(4 + 2 a^{2} - 2 a) - (3 a^{2} - 8 a + 7)$ $(4+2a^2-2a)-(3a^2-8a+7)$

$:.=(2a^2-2a+4)-(3a^2-8a+7)$

$:.=2a^2-2a+4-3a^2+8a-7$

$:.=-a^2+6a-3$

How do you find the sum or difference of (4+2a^2-2a)-(3a^2-8a+7)(4+2a2−2a)−(3a2−8a+7)(4+2a^2-2a)-(3a^2-8a+7)?