How do you find the sum or difference of $(a^3-3a^2+4)-(4a^2+7)$ ?

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Answer 1 · 2018-03-22T18:14:25

$a^3-7a^2-3$

You need to remove the brackets.

$(a^3 -3a^2+4)-(4a^2+7)$

$=a^3 -3a^2+4-4a^2-7$

$a^3-7a^2-3$

How do you find the sum or difference of (a^3-3a^2+4)-(4a^2+7)(a^3-3a^2+4)-(4a^2+7)?