How do you find the sum or difference of $(cd^2+2cd-4)+(-6+4cd-2cd^2)$ ?

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Answer 1 · 2016-12-21T14:42:29

$-cd^2 + 6cd - 10$

First, you need to expand the terms within parenthesis. Pay special attention to the signs of each term:

$cd^2 + 2cd - 4 + (-6) + 4cd + (-2cd^2)$

$cd^2 + 2cd - 4 - 6 + 4cd - 2cd^2$

Next we can group like terms:

$cd^2 - 2cd^2 + 2cd + 4cd - 4 - 6$

Then finally, we can combine like terms:

$(1 - 2)cd^2 + (2 + 4)cd - 10$

$-1cd^2 + 6cd - 10$

$-cd^2 + 6cd - 10$

How do you find the sum or difference of (cd^2+2cd-4)+(-6+4cd-2cd^2)(cd^2+2cd-4)+(-6+4cd-2cd^2)?