How do you find the trigonometric form of $z = 8 - 8 i$ $z = 8 − 8i$ ?

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Answer 1 · 2015-07-10T11:43:18

I found: $z=8sqrt(2)[cos(315°)+isin(315°)]$

Have a look:
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hope it is understandable.

How do you find the trigonometric form of z = 8 − 8i z=8−8iz = 8 − 8i ?