How do you find the value of 325 x 10^-2?

1 Answer
Oct 2, 2015

It is 3.25

Explanation:

If you have to calculate the value of an expression a*10^n for an integer value of n, the easiest way is to write the value of a as a decimal fraction (adding .0 if a is integer) and next move the decimal point |a| places tpo the left if a<0 or to the right if a>0

In this case you have:

a=325, n=-2, so:

1) You write a as a decimal fraction 325.0
2) n<0, so you move the decimal point 2 places left, so you get 3.250
3) Finally you can cross out any zeros at the right end of the number to get 3.25