Question

How do you find the value of `arcsin(-sqrt3/2)`?

Answer 1

`(4pi)/3, (5pi)/3`

Explanation:

Use trig table and unit circle:
`sin x = - sqrt3/2` -->
arc `x = - (pi)/3` and arc `x = - (2pi)/3`
Co-terminal arc of `(-pi/3) --> (4pi)/3`
Co-terminal of `(-2pi)/3 --> (5pi)/3`
Answers for `(0, 2pi)`
`(4pi)/3, (5pi)/3`