How do you find the value of $cos ((14pi)/3)$ ?

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Answer 1 · 2016-08-01T03:44:58

$- 1/2$

Trig table and unit circle -->
$cos ((14pi)/3) = cos ((2pi)/3+ (12pi)/3) = cos ((2pi)/3 + 4pi) =$
$= cos ((2pi)/3) = -1/2$

How do you find the value of cos ((14pi)/3)cos ((14pi)/3)?