Question

How do you find the value of `csc ((pi)/2)`?

Answer 1

`csc(theta) = 1/sin(theta)`

`sin(pi/2) = 1` (this is a basic relation)

`rarr csc(pi/2) = 1`

Answer 2

Well, `csc(x)=1/sin(x)` so basically, I would find `sin(pi/2)` and use it to get:
`csc(pi/2)=1/(sin(pi/2))=1/1=1`

Graphically:

Remember also that: