How do you find the value of x: log_x (121/289) = 2?

1 Answer
maganbhai P.
Mar 14, 2018

x=11/17

Explanation:

color(red)((1)log_aX=n<=>X=a^n)
color(red)((2)log_aX^n=nlogX)
We have,
log_x(121/289)=2=>log_x(11/17)^2=2
=>2*log_x(11/17)=2
=>log_x(11/17)=1
=>11/17=x^1=>x=11/17

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