How do you find the vector v with the given magnitude of 9 and in the same direction as #u=<2,5>#?

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Answer 1 · 2017-12-17T19:34:46

See below.

A vector a with given magnitude in the direction of b, is given by:

#(||a||*b)/||b||#

#||u||=sqrt((2)^2+(5)^2)=sqrt(29)#

#||v||=9#

#(9(2+5))/sqrt(29)#

#18/sqrt(29)hati+45/sqrt(29)hatj# or #((18/sqrt(29)),(45/sqrt(29)))#