How do you find the vertex for $y=x^2-x-2$ ?

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Answer 1 · 2017-08-02T10:26:32

Vertex is at $(1/2 , -2 1/4)$

$y= x^2 -x -2 or y= x^2 -x +(1/2)^2 -1/4 -2$ or

$y= (x-1/2)^2 -9/4$ , Comparing with vertex form of equation

$y= a (x-h)^2+k ; (h,k)$ being vertex , we find here

$h=1/2 , k = -9/4$ . So vertex is at $(1/2 , -2 1/4)$

graph{x^2-x-2 [-10, 10, -5, 5]} [Ans]

How do you find the vertex for y=x^2-x-2 y=x^2-x-2?