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How do you find the volume of a solid that is generated by rotating the region enclosed by the graph of $y = \sqrt{x}$ $y=sqrt(x)$ and the lines $x = 1$ $x = 1$ , $x = 2$ $x = 2$ , and $y = 1$ $y = 1$ , rotated about the x-axis?

1 Answer

Mar 15, 2015

Your solid should look lke a ring:
enter image source here
I would use a small cylinder "projected" along your solid:

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