Question

How do you find the x and y intercept of `-16x^2+24x-5`?

Answer 1

Solve `y = - 16x^2 + 24x - 5.`
Answers: 1/4 and 5/4

Explanation:

To find y-intercept, make x = 0 --> y = - 5
To find x-intercepts, solve `y = - (16x^2 - 24x + 5) = 0 (1)`
I use the new Transforming Method (Google, Yahoo Search).
Transformed equation: `y' = x^2 - 24x + 80.(2)` Roots have same sign.
Factor pairs of (80) -->...(2, 40)(4, 20). This sum is 24 = -b. Then the 2 real roots are: y1 = 4 and y2 = 20.
Back to original equation (1), the 2 real roots are: `x1 = (y1)/a = 4/16 = 1/4` and `x2 = (y2)/a = 20/16 = 5/4`