How do you find the x and y intercept of $y = x^{2} - 2 x - 3$ $y=x^2-2x-3$ ?

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How do you find the x and y intercept of $y = x^{2} - 2 x - 3$ $y=x^2-2x-3$ ?

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Answer 1 · 2015-07-30T04:35:04

$y = x^{2} - 2 x - 3 .$ $y = x^2 - 2x - 3.$

Explanation:

To find y-intercept, make x = 0 --> y = - 3
To find the 2 x-intercepts, make y = 0 and solve the quadratic equation: $y = x^{2} - 2 x - 3 = 0$ $y = x^2 - 2x - 3 = 0$ .
Since (a - b + c = 0), use the shortcut. Two real roots are $x = - 1$ $x = - 1$ and $x = - \frac{c}{a} = 3$ $x = -c/a = 3$

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How do you find the x and y intercept of $y = x^{2} - 2 x - 3$ $y=x^2-2x-3$ ?

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Explanation:

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Science

Math

Humanities

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How do you find the x and y intercept of y=x^2-2x-3y=x2−2x−3y=x^2-2x-3?

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Explanation:

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How do you find the x and y intercept of $y = x^{2} - 2 x - 3$ $y=x^2-2x-3$ ?