How do you find the x and y intercepts for $2x+y= -3$ ?

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Answer 1 · 2016-03-03T01:40:29

The x-intercept is $(-3/2,0)$ .

The y-intercept is $(0,-3)$ .

The x-Intercept is the value of $x$ when $y=0$ , and the y-intercept is the value of $y$ when $x=0$ .

X-Intercept

$2x+y=-3$

Set $y=0$ and solve for $x$ .

$2x+0=-3$

Simplify.

$2x=-3$

Divide both sides by $2$ .

$x=-3/2$

The x-intercept is $(-3/2,0)$ .

Y-Intercept

$2x+y=-3$

Set $x=0$ .

$2(0)+y=-3$

Simplify.

$y=-3$

The y-intercept is $(0,-3)$ .

graph{2x+y=-3 [-9.81, 10.19, -6.76, 3.24]}

How do you find the x and y intercepts for 2x+y= -32x+y= -3?