How do you find the x and y intercepts for $2 x + y = 5$ $2x+y=5$ ?

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Answer 1 · 2018-05-10T14:00:07

$y_{intercept} = + 5 . \to (x, y) = (0, 5)$ $y_("intercept") = +5 color(white)(.)->(x,y)=( 0,5)$

$x_{intercept} = + \frac{5}{2} \to (x, y) = (\frac{5}{2}, 0)$ $x_("intercept")=+5/2 ->(x,y)=(5/2,0)$

color(white)(

Write as: $y = - 2 x + 5$ $color(green)(y=-2xcolor(red)(+5))$

$y_{intercept} = 5$ $color(red)(y_("intercept") = 5)$
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The plotted line crosses the x-axis at $y = 0$ $y=0$

Set $y = 0 = - 2 x + 5$ $y=0=-2x+5$

Subtract 5 from both sides

$0 - 5 = - 2 x + 5 - 5$ $0-5=-2x+5-5$

$- 5 = - 2 x$ $-5=-2x$

Divide both sides by -2

$\frac{- 5}{- 2} = \frac{- 2}{- 2} x$ $(-5)/(-2)=(-2)/(-2)x$

$+ \frac{5}{2} = x_{intercept}$ $+5/2=x_("intercept")$

Tony B

How do you find the x and y intercepts for 2x+y=52x+y=5?