How do you find the x and y intercepts for f(x)=4x^2-36?

1 Answer
May 23, 2018

"x-intercepts "=+-3," y-intercept "=-36

Explanation:

"to find the intercepts, that is where the graph crosses"
"the x and y axes"

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercepts"

x=0toy=0-36=-36larrcolor(red)"y-intercept"

y=0to4x^2-36=0

"add 36 to both sides and divide by 4"

4x^2=36rArrx^2=9

color(blue)"take the square root of both sides"

x=+-sqrt9larrcolor(blue)"note plus or minus"

x=+-3larrcolor(red)"x-intercepts"