How do you find the x intercept and y intercept for $y=x^2-x-2$ ?

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Answer 1 · 2016-03-01T19:23:20

To find the x-intercepts let y=0; $0=x^2-x-2 = (x-2)(x+1) -> x =12 or x = -1$
To find the y intercept let x = 0;
$y=0-0-2=-2$

To find x intercept let y = 0 and solve for x and to find the y-intercept let x=0 and solve for y

How do you find the x intercept and y intercept for y=x^2-x-2 y=x^2-x-2?