How do you find the x intercepts for #3x^2 - 4x - 8 = 0#? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Nghi N. Jul 6, 2015 Solve: #y = 3x^2 - 4x - 8 = 0# Explanation: #D = d^2 = b^2 - 4ac = 16 + 96 = 112 # -> #d = +- 4sqrt7# #x = 8/6 +- (4sqrt7)/6 = 4/3 +- (2sqrt7)/3# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 1534 views around the world You can reuse this answer Creative Commons License