How do you find the x intercepts of y=sinpix+cospix?

1 Answer
Feb 20, 2018

x = k - 1/4" " for any integer k

Explanation:

Note that:

y = sin pi x + cos pi x

color(white)(y) = sqrt(2)(sqrt(2)/2 sin pi x + sqrt(2)/2 cos pi x)

color(white)(y) = sqrt(2)(sin (pi/4) sin pi x + cos (pi/4) cos pi x)

color(white)(y) = sqrt(2) sin (pi/4 + pi x)

Also note that:

sin theta = 0" " if and only if theta = k pi for some integer k

So we require:

pi/4 + pi x = k pi

Dividing both sides by pi, this becomes:

1/4 + x = k

Then subtracting 1/4 from both sides we find:

x = k - 1/4" " for any integer k