How do you find the y intercept for $y = 12 x^{2} - 35 x + 8$ $y = 12x^2 - 35x + 8$ ?

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How do you find the y intercept for $y = 12 x^{2} - 35 x + 8$ $y = 12x^2 - 35x + 8$ ?

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Answer 1 · 2018-04-06T19:31:53

The $y$ $y$ -intercept is $(0, 8)$ $(0, 8)$ .

Explanation:

$y$ $y$ -intercept is the value at which $x$ $x$ is zero , or the value of $y$ $y$ which the point on the line of the graph crosses the $y$ $y$ axis .

Since $x$ $x$ has to be $0$ $0$ , let's substitute $0$ $0$ for $x$ $x$ in the equation:
$y = 12 x^{2} - 35 x + 8$ $y = 12x^2 - 35x + 8$
$y = 12 {(0)}^{2} - 35 (0) + 8$ $y = 12(0)^2 - 35(0) + 8$
$y = 0 - 0 + 8$ $y = 0 - 0 + 8$
$y = 8$ $y = 8$

Finally, since a $y$ $y$ -intercept is a point, we must write it as one. So the point is $(0, 8)$ $(0, 8)$ .

If we are to graph this, we can see that the graph does indeed have a $y$ $y$ -intercept of $(0, 8)$ $(0, 8)$ :
enter image source here

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How do you find the y intercept for $y = 12 x^{2} - 35 x + 8$ $y = 12x^2 - 35x + 8$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you find the y intercept for y = 12x^2 - 35x + 8y=12x2−35x+8y = 12x^2 - 35x + 8?

1 Answer

Explanation:

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How do you find the y intercept for $y = 12 x^{2} - 35 x + 8$ $y = 12x^2 - 35x + 8$ ?